K
khaiproqn81
Em trả lời nè mod
$8x^3(y+z)-y^3(z+2x)-z^3(2x-y)$
$=>8x^3[(z+2x)-(2x-y)]-y^3(z+2x)-z^3(2x-y)$
$=>8x^3(z+2x)-8x^3(2x-y)-y^3(z+2x)-z^3(2x-y)$
$=>8x^3(z+2x)-y^3(z+2x)-8x^3(2x-y)-z^3(2x-y)$
$=>(z+2x)(2x-y)(4x^2+2xy+y^2)-(z+2x)(2x-y)(4x^2-2xz+x^2)$
$=>(z+2x)(2x-y)[(4x^2+2xy+y^2)-(4x^2-2xz+x^2)]$
$=>(z+2x)(2x-y)[2x(y+z)+(y+z)(y-z)]$
$=>(z+2x)(2x-y)(y+z)(2x+y-z)$
Nếu sai chỗ nào thì mong thông cảm nha
$8x^3(y+z)-y^3(z+2x)-z^3(2x-y)$
$=>8x^3[(z+2x)-(2x-y)]-y^3(z+2x)-z^3(2x-y)$
$=>8x^3(z+2x)-8x^3(2x-y)-y^3(z+2x)-z^3(2x-y)$
$=>8x^3(z+2x)-y^3(z+2x)-8x^3(2x-y)-z^3(2x-y)$
$=>(z+2x)(2x-y)(4x^2+2xy+y^2)-(z+2x)(2x-y)(4x^2-2xz+x^2)$
$=>(z+2x)(2x-y)[(4x^2+2xy+y^2)-(4x^2-2xz+x^2)]$
$=>(z+2x)(2x-y)[2x(y+z)+(y+z)(y-z)]$
$=>(z+2x)(2x-y)(y+z)(2x+y-z)$
Nếu sai chỗ nào thì mong thông cảm nha