T
tongdinhthanh
bai nay minh lam the nay khong biet la cach nay co hay khongCâu 1: [tex]\left{\begin{\sqrt{y}(\sqrt{x}+\sqrt{x+3})=3\\ {\sqrt{x}+\sqrt{y}=x+1}[/tex]
tu pt 1 ta co can y duoc bieu dien qua bieu thuc chi chua x sau do thay vao pt 2
ban di xet ham so thi thay ham so do luon nghich bien => co nghiem duy nhat x= 1 va tim ra y
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