+ [imath]y=\sqrt{2x}+ \sqrt{3}x^2+1[/imath]
+ [imath]y'= \dfrac{(2x)'}{2 \sqrt{2x}} + 2 \sqrt{3}x = \dfrac{2}{2 \sqrt{2x}} + 2 \sqrt{3}x = \dfrac{1}{ \sqrt{2x}} + 2 \sqrt{3}x [/imath]
[imath]y' \left ( \dfrac{1}{2} \right ) = \dfrac{1}{ \sqrt{2. \dfrac{1}{2}}} + 2 \sqrt{3}. \dfrac{1}{2} =1+\sqrt{3}[/imath]