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lovelycat_handoi95
Bài 135: [TEX]1+sinx - cosx - sin2x + cos2x =0[/TEX]
[TEX]<=>1+sinx-cosx-2sinxcosx+2cos^2x-1=0 [/TEX]
[TEX]<=> sinx(1-2cosx)-cosx(1-2cosx)=0[/TEX]
[TEX]<=>(sinx-cosx)(1-2cosx)=0 [/TEX]
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