a) PTHH: Fe + 2HCl -> FeCl2 + H2
...............0,225..0,45....0,225.....0,225
nFe = 12,6/56 =0,225 mol
nH2 = 0,225.1/1 = 0,225 mol
VH2 = 0,225.22,4 = 5,04 l
b) PTHH: FeO + H2 -> Fe + H2O
..........................0,225.........
nFe = 0,225.1/1 = 0,025 mol
mFe = 0,225.56 = 12,6g