[tex]\frac{x}{24} + \frac{x-6}{32} = \frac{2x-6}{27}[/tex]
$\dfrac{x}{24}+\dfrac{x-6}{32}=\dfrac{2x-6}{27}
\\\Leftrightarrow \dfrac{36x+27(x-6)-32(2x-6)}{864}=0
\\\Leftrightarrow 36x+27x-162-64x+192=0
\\\Leftrightarrow 30-x=0
\\\Leftrightarrow x=30$
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