$\color{Red}{\fbox{★Hóa 9★}}\color{Magenta}{\fbox{game nối chuỗi phản ứng }}$

[longlongago]

Ba(HCO3)2 + Na2SO4 ==> Ba(HCO3)2Na2SO4

 

[kagaminex]

Ba(HCO3)2 + Na2SO4 ==> Ba(HCO3)2Na2SO4

hình như là nhầm rồi bạn ơi!! đây là pứ trao đổi bình thường thôi

$Ba(HCO_3)_2+Na_2SO_4 \rightarrow BaSO_4+2NaHCO_3$


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:M040::M040::M040::M040::M040:

 

[buivanbao123]

$NaHCO_3+Ca(NO_3)_2----->Ca(HCO_3)_2+NaNO_3$

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[rikadu]

$NaHCO_3+Ca(NO_3)_2----->Ca(HCO_3)_2+NaNO_3$

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$Ca(HCO_3)_2 + 2HCL ---> CaCl_2 + 2H2O + CO2↑$ >-

 

[buivanbao123]

$CaCL_2+AgNO_3------->AgCL+CaNO_3$

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[flytoyourdream99]

$Ca(HCO_3)_2 + 2HCL ---> CaCl_2 + 2H2O + CO2↑$ >-

$ H_20 + Cl_2 --> HCl + HCl0 $ .

 

[kagaminex]

$ H_20 + Cl_2 --> HCl + HCl0 $ .

$HCl+NH3\rightarrow NH4Cl$

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:M040::M040::M040::M040::M040:

 

[buivanbao123]

$NH_4CL------>NH_3+HCl$ (nhiệt phân)

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[kagaminex]

$NH_4CL------>NH_3+HCl$ (nhiệt phân)

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$Ca+2HCl\rightarrow H_2+CaCl_2$

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:M040::M040::M040::M040::M040:

 

[buivanbao123]

$CaCL_2+Hg(NO_3)_2------->HgCL_2+CaNO_3$


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[flytoyourdream99]

$CaCL_2+Hg(NO_3)_2------->HgCL_2+CaNO_3$


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$ CaN0_3 + Na_2C0_3 --> NaN0_3 + CaC0_3 $ .

 

[longlongago]

CaCO3(s) + H2O(l) ==> CO2(g) + Ca(OH)2(aq)

 

[kagaminex]

$CaCL_2+Hg(NO_3)_2------->HgCL_2+CaNO_3$


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$Ca(NO_3)_2$ nha bạn viết nhầm rùi hj

$Ca(NO_3)_2--t^o-->Ca(NO_2)_2+O_2$

CHẾT MÌNH NHÌN NHẦM RÙI >>>SORRY MN
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:M040::M040::M040::M040::M040:

 

[buivanbao123]

$o_2+h_2---->h_2o$


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[kagaminex]

$o_2+h_2---->h_2o$


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$H_2O+Na_2O-->2NaOH$

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:M040::M040::M040::M040::M040:

 

[longlongago]

2NaOH + H2SO4 ==> Na2SO4 + 2H2O

 

[kagaminex]

2NaOH + H2SO4 ==> Na2SO4 + 2H2O

$Na_2SO_4+4H_2--t^o;xt--> Na_2S+4H_2O$

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[longlongago]

4H2O + Na2S + 4Br2 --> Na2SO4 + 8HBr

 

[kagaminex]

4H2O + Na2S + 4Br2 --> Na2SO4 + 8HBr

$2HBr\rightarrow H_2+Br_2$

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[flytoyourdream99]

$2HBr\rightarrow H_2+Br_2$

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$H_2 + Fe_20_3 ---> Fe + H_20$ .