$\color{Red}{\fbox{★Hóa 9★}}\color{Magenta}{\fbox{game nối chuỗi phản ứng }}$

[kobato_2509]

$Mg(OH)_2 -------> MgO + H_2O$
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[kagaminex]

$Mg(OH)_2 -------> MgO + H_2O$
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$MgO+2HCl-->MgCl_2+H_2$

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:M040::M040::M040::M040::M040::M040:

 

[kobato_2509]

$MgCl_2 + 2AgNO_3 ----> Mg(NO_3)_2 + 2AgCl$
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[buivanbao123]

$Mg(NO_3)_2+NaOH--->Mg(OH)_2+NaNO_3$

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[kobato_2509]

$Mg(NO_3)_2+NaOH--->Mg(OH)_2+NaNO_3$

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$2NaNO_3 ------> 2NaNO_2 + 3O_2$ (điều kiện: $t^o$)

 

[kagaminex]

$2NaNO_3 ------> 2NaNO_2 + 3O_2$ (điều kiện: $t^o$)

$NaNO_2+HCl \rightarrow NaCl+HNO_2$

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:M040::M040::M040::M040::M040::M040::M040:

 

[buivanbao123]

$Nacl+AgNO_3--->NaNO_3+AgCL$


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[anhto2011]

NaNO_3 + HCl ----> NaCl + HNO_3

.............................."...................

 

[buivanbao123]

$koh+hno_3----->kno_3+h_2o$

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[anhto2011]

H2O + Ba ---> Ba(OH)2




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..
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[kobato_2509]

H2O + Ba ---> Ba(OH)2




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..
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sai rùi!
Nối tiếp $H_2O + Bao ----> Ba(OH)_2$
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[bcd_hau_vodoi]

$ Ba(OH)_2 + Cu(NO_3)_2 \rightarrow Ba(NO_3)_2 + Cu(OH)_2 $....................:khi (70):

 

[kobato_2509]

$Cu(OH)_2 ---------> CuO +H_2O$
ĐK: $t^o$
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[kagaminex]

$Cu(OH)_2 ---------> CuO +H_2O$
ĐK: $t^o$
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$CuO+2HCl \rightarrow CuCl_2+H_2O$

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:M040::M040::M040::M040::M040:

 

[hinhthao2]

CuO + 2HNO3 --------------------> Cu(NO3)2 + H2O
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[kagaminex]

CuO + 2HNO3 --------------------> Cu(NO3)2 + H2O
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làm tiếp của mình chứ bạn mà thui sao sao cũng

$2Cu(NO_3)_2--t^o-->2CuO+4NO_2+O_2$

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:M040::M040::M040::M040::M040:

 

[flytoyourdream99]

làm tiếp của mình chứ bạn mà thui sao sao cũng

$2Cu(NO_3)_2--t^o-->2CuO+4NO_2+O_2$

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:M040::M040::M040::M040::M040:

$0_2 + Na ---> Na_20 $ .

 

[buivanbao123]

$Na_2O+HCL------>NaCL+H_2O$

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[kagaminex]

$Na_2O+HCL------>NaCL+H_2O$

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$2H_2O--đp-->2H_2+O_2$

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:M040::M040::M040::M040::M040:

 

[bcd_hau_vodoi]

$ H_2 + O_2 \rightarrow H_2O $

Điều kiện: nhiệt độ............