300ml = 0,3l
n_{CuCl_{2}}= C_{M}.V = 0,5.0,3=0,15 (mol)
a. PTHH
CuCl_{2} + 2NaOH \rightarrow 2NaCl + Cu(OH)_{2} CuCl_{2} + 2NaOH \rightarrow 2NaCl + Cu(OH)_{2} (1)
Cu(OH)_{2}\overset{t^{0}}{\rightarrow} CuO + H_{2}O (2)
b. Theo PTHH (1) ta có
n_{Cu(OH)_{2}}=\frac{0,15.1}{1}=0,15 (mol)
Theo đề ta...