Kết quả tìm kiếm

1. \frac{18x^4y^3-24x^3y^4+12x^3y^3 }{ -6x^2y^3 }=\frac{6x^3y^3(3x-4y+2)}{-6x^2y^3}=-x(3x-4y+2) 2.. a,x^3-2x^2+5x-10= x^2(x-2)+5(x-2)= (x^2+5)(x-2) b,x^3-x^2-4x^2+8x-4= x^2(x-1)-4(x-1)^2=(x-1)(x^2-4(x-1))=(x-1)(x^2-4x+4)=(x-1)(x-2)^2...

a, M=x^{2}+y^{2}-x+8y+17=x^2-x+\frac{1}{4}+y^2+8y+16+\frac{3}{4}=(x-\frac{1}{2})^2+(y+4)^2+\frac{3}{4}\geq \frac{3}{4}

x^2+2x+2017=x^2+2x+1+2016=(x+1)^2+2016\geq 2016 \Leftrightarrow x=-1

Part 1 a,(x^3)^2-(x+1)(x-1)=1\Leftrightarrow x^6-x^2+1=1\Leftrightarrow x^6-x^2=0\Leftrightarrow x^2(x^3-1)=0\Leftrightarrow x^2(x-1)(x^2+x+1)\Leftrightarrow x=0;x=1 b,(x-2)^2-3(x-2)=0\Leftrightarrow (x-2)(x-2-3)=0\Leftrightarrow (x-2)(x-5)=0\Leftrightarrow x=2;x=5...

a) 3x^2 - 9x + 5=2x^2+x^2-9x+\frac{81}{4}-\frac{61}{4}=2x^2+(x-\frac{9}{2})^2-\frac{61}{4}\geq -\frac{61}{4} b) ( 1 - x ) ( 3x + 4 )=-3x^2-x+4=-3(x^2+\frac{1}{3}x+\frac{1}{36})+\frac{49}{12}=-3(x+\frac{1}{6})^2+\frac{49}{12}\leq \frac{49}{12} c) x^2 + 5y^2 - 2xy + y +...

1. a,3x^2(4x^2-2x+3)=12x^4-6x^3+9x^2 b,(2x^2-x)(x+5)=2x^3-x^2+10x^2-5x=2x^3+9x^2-5x c,\frac{(3x^4y^3-6x^3y^2+15xy^2)}{6xy^2}=\frac{3xy^2(x^3y-2x^2+5)}{6xy^2}=\frac{x^3y-2x^2+5}{2} 2. a,9x^2y^2+15x^2y-12xy=3xy(3xy+5x-12) b,x^2+6x+9=(x+3)^2...

(2x+1)(2x-1)-(x-4)^2=4x^2-1-x^2+8x-16=3x^2+8x-17

25^{x} : 5^{x+1} = 125\Leftrightarrow 5^{2x}: 5^{x+1}=5^3\Rightarrow 2x-x-1=3\Rightarrow x=4

1. a,4x^{2}-2x=2x(2x-1) b,9x^{2}-y^{2}+2y-1=(3x)^2-(y-1)^2=(3x+y-1)(3x-y+1) 2. a) x(x-3)-4x+12=0\Leftrightarrow x(x-3)-4(x-3)=0\Leftrightarrow (x-4)(x-3)=0\Leftrightarrow x=4;x=3 2x^{2}-x-6=0\Leftrightarrow 2x^2-4x+3x-6=0\Leftrightarrow 2x(x-2)+3(x-2)=0\Leftrightarrow...

x^2-x+6=x^2-2.x.\frac{1}{2}+(\frac{1}{2})^2+\frac{23}{4}=(x-\frac{1}{2})^2+\frac{23}{4}\geq \frac{23}{4}>0

\sqrt{\frac{x-2\sqrt{x}+1}{x+2\sqrt{x}+1}}=\sqrt{\frac{(\sqrt{x}-1)^2}{(\sqrt{x}+1)^2}}=\frac{1-\sqrt{x}}{\sqrt{x}+1}

Chào bạn !