Đặt [tex]R_2=x(\Omega) \Rightarrow R_{AB}=4+\frac{6x}{6+x}=\frac{10x+24}{6+x}[/tex]
[tex]I_3=\frac{U_{AB}}{R_{AB}}=\frac{6(6+x)}{10x+24}=\frac{3(6+x)}{5x+12}[/tex]
[tex]I_2=I_3.\frac{R1}{R_1+R_2}=\frac{3(6+x)}{5x+12}.\frac{6}{x+6}=\frac{18}{5x+12}=\frac{2}{3}\Rightarrow R_2=x=3(\Omega)[/tex]