tính nồng độ H+

T

thupham22011998

a/ CH3COONa−−>CH3COO−+Na+CH_3COONa-->CH_3COO^-+Na^+

CH3COO−+H2O<−−>CH3COOH+OH−CH_3COO^-+H_2O<-->CH_3COOH+OH^-

Gọi độ điện li của CH3COO−=xCH_3COO^-=x

kb của CH3COO−CH_3COO^- là 5,71.10−105,71.10^{-10}

\Rightarrow [OH−].[CH3COOH][CH3COO−]=5,71.10−10\frac{[OH^-].[CH_3COOH]}{[CH_3COO^-]}=5,71.10^{-10}

\Leftrightarrow x20,1−x=5,71.10−10\frac{x^2}{0,1-x}=5,71.10^{-10}

vì x<<0,1−−>x=2,4.10−5=[OH−]x << 0,1 --> x=2,4.10^{-5}=[OH^-] -->[H+]=4,2.10−10[H^+]=4,2.10^{-10}

b, tương tự
 
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