$x - \dfrac{1}{4} = \dfrac{9}{x-1}$
$\Rightarrow \dfrac{4x - 1}{4} = \dfrac{9}{x-1}$
$\Rightarrow (4x - 1)(x - 1) = 36$
Tìm ước là xong
$\dfrac{2}{3} + \dfrac{1}{3} : |x-2| = 1$
$\Rightarrow \dfrac{1}{3} : |x-2| = \dfrac{1}{3}$
$\Rightarrow |x-2| = 1$
$\Rightarrow x = 3$ hoặc $x =1$