Hai đèn sáng bình thường nên $U_đ=U_{đm}$
$U_1=24V ⇒ I_1=\dfrac{\mathscr{P_1}}{U_1}=0,5A$
$U_2=12V ⇒ I_2=\dfrac{\mathscr{P_2}}{U_2}=0,75A$
$U_b=U_1-U_2=12V$
$I_b=I_2=0,75A$
$R_b=\dfrac{U_b}{I_b}=16Ω$
Hai đèn sáng bình thường nên $U_đ=U_{đm}$
$U_1=24V ⇒ I_1=\dfrac{\mathscr{P_1}}{U_1}=0,5A$
$U_2=12V ⇒ I_2=\dfrac{\mathscr{P_2}}{U_2}=0,75A$
$U_b=U_1-U_2=12V$
$I_b=I_2=0,75A$
$R_b=\dfrac{U_b}{I_b}=16Ω$