[imath]n_{H_2}(1)=0,02[/imath]
[imath]n_{H_2}(2)=0,035[/imath]
P1 thoát khí ít hơn P2=>P1 Al dư
Gọi x,y là số mol K,Al
P1:
[imath]K+H_2O \rightarrow KOH+\frac{1}{2}H_2[/imath]
x---------------------x------0,5x
[imath]KOH+Al+H_2O \rightarrow KAlO_2 + \frac{3}{2}H_2[/imath]
x-------------------------------------------1,5x
P2:
[imath]K+H_2O \rightarrow KOH+\frac{1}{2}H_2[/imath]
x----------------------x--------0,5x
[imath]KOH+Al+H_2O \rightarrow KAlO_2 + \frac{3}{2}H_2[/imath]
y----------y--------------------------------1,5y
2x=0,02
0,5x+1,5y=0,035
=>x=0,01, y=0,02
=>m=(0,01.39+0,02.27).2=1,86 g=>Câu A
Bạn tham khảo nhé!