1. [tex]\frac{x^2-1}{x^2+1}=1-\frac{2}{x^2+1}[/tex]
Vì [tex]x^2\geq 0\Rightarrow x^2+1\geq 1\Rightarrow \frac{2}{x^2+1}\leq 2\Rightarrow -\frac{2}{x^2+1}\geq -2[/tex]
[tex]\Rightarrow \frac{x^2-1}{x^2+1}\geq 1-2=-1[/tex]
Dấu "=" xảy ra [tex]\Leftrightarrow x^2=0\Leftrightarrow x=0[/tex]