phương trình

S

soccan

$9x-9+x^2-6x\sqrt{x-1}=x^2-6x+6\\
15(x-1)-6x\sqrt{x-1}=0\\
3\sqrt{x-1}(5\sqrt{x-1}-2x)=0$
xét $x=1$ không thỏa mãn
xét $5\sqrt{x-1}=2x \longleftrightarrow 4x^2-25x+25=0 \longleftrightarrow x_1=5,x_2=\dfrac{5}{4}$
vậy $S=\left \{ \dfrac{5}{4};5 \right \}$
 
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