ta có A(2,0,3), B(0,3-5),C(2,0,5)
[tex]\vec{AB}(-2,0,-5),\vec{AC}(0,-3,-5)\Rightarrow \vec{n}_{(ABC)}=[\vec{AB},\vec{AC}]=(-15,-10,6)[/tex]
=> (ABC) : -15x-10y+6z+60=0
d(M,(ABC)) = [tex]\frac{\left | -15.2-10.3+6.-5+60 \right |}{\sqrt{(-15)^{2}+(-10)^{2}+6^{2}}}=\frac{30}{19}[/tex]