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H

hocmai.hoahoc

Bài giải

[TEX]\begin{array}{l} n_O = \frac{{4,8}}{{16}} = 0,3mol \\ m_{H^ + } = 2n_O = 0,6mol \\ \Rightarrow 1.V + 0,5.2.V = 0,6 \Rightarrow V = 0,3lit \\ \end{array}\[/TEX]
 
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