[Hóa 8]

T

thupham22011998

$2Al+3Cl_2-t^o->2AlCl_3$

Ta có: $n AlCl_3=13,5:133,5=9/89 mol$

Theo pthh, ta có: $n Cl_2=3/2.n AlCl_3=27/178 mol$

-->$V=3,398l$
 
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