[hóa 11] nhiệt phân muối nitrat

M

metla2011

[TEX]2R(NO_3)_n---> R_2O_m+2nNO_2+(n-\frac{m}{2})O_2[/TEX]
2(R+62n)-----2R+16m-----
--36-----------16-----
[TEX]\frac{2R+124n}{36}=\frac{2R+16m}{16}[/TEX]
[TEX]\Rightarrow R=49,6n-14,4m[/TEX]
[TEX]\Rightarrow R=Fe (n=2; m=3)[/TEX]
 
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