[ Hóa 11 ] CO2 + NaOH + Ca(OH)2

L

leduydon

H

huy266

[tex]n_{OH^{-}}=2n_{H_{2}}=2\times 0,3=0,6(mol)[/tex]
[tex]\Rightarrow n_{K}=n_{Ba}=0,2(mol)[/tex]
[tex]CO_{2}+2OH^{-}\rightarrow CO_{3}^{2-}+H_{2}O[/tex]
0,025--->0,05------>0,025(mol)
[tex]Ba^{2+}+CO_{3}^{2-}\rightarrow BaCO_{3}[/tex]
0,2(dư)--0,025------>0,025
m kết tủa =4,925(g)
 
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