(Hóa 10) Ôn tập

C

chaugiang81


PTHH :
$CaO + 2H_2O --> Ca(OH)_2 + H_2 $
$nCa = 0.5 : 40= 0.0125 mol$
$=>nCa(OH)_2 = 0.0125 mol$
Vdd sau p.ư la :500ml = 0.5 l
$=>CM Ca(OH)_2= .... $
 
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