View attachment 215513
a) [imath]SA\bot (ABCD)[/imath]
[imath]\Rightarrow (SC,(ABCD))=\widehat{SCA}[/imath]
[imath]AC=a\sqrt5[/imath]
[imath]\tan \widehat{SCA}=\dfrac{SA}{AC}=\dfrac{\sqrt{30}}5[/imath]
[imath]\Rightarrow (SC,(ABCD))=\arctan \dfrac{\sqrt{30}}5[/imath]
b) [imath]SA\bot (ABCD)[/imath]
[imath]\Rightarrow (SB,(ABCD))=\widehat{SBA}[/imath]
[imath]\tan \widehat{SBA}=\dfrac{SA}{AB}=\sqrt5[/imath]
[imath]\Rightarrow (SB,(ABCD))=\arctan \sqrt5[/imath]
c) Kẻ [imath]BE\bot AC[/imath]
[imath]SA\bot BE (SA\bot (ABCD))[/imath]
Suy ra [imath]BE\bot (SAC)[/imath]
[imath]\Rightarrow (SB,(SAC))=\widehat{BSE}[/imath]
[imath]AB=\sqrt{AS^2+AB^2}=a\sqrt7[/imath]
[imath]BE=\dfrac{2a\sqrt5}5[/imath]
[imath]\sin \widehat{BSE}=\dfrac{BE}{SB}=\dfrac{2\sqrt{35}}{35}[/imath]
[imath]\Rightarrow (SB,(ABCD))=\arcsin \dfrac{2\sqrt{35}}{35}[/imath]
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