6) a) nH2= 1,792/22,4 = 0,08
Zn + 2CH3COOH --> (CH3COO)2Zn + H2
0,08-----0,16-------------------0,08----------0,08
-->mZn pư=0,08.65=5,2g
m(CH3COO)2Zn=0,08.183=14,64g
b) nBa(OH)2=0,2.0,5=0,1
ptpư: 2CH3COOH + Ba(OH)2 --> (CH3COO)2Ba + 2H2O
------------0,2--------------0,1
-->nCH3COOH dư=0,2
-->nCH3COOHbđ=0,2+0,16=0,36
-->CM(ddCH3COOH)=0,36/0,5=0,72M
5) a) ptpư: Zn + 2CH3COOH --> (CH3COO)2Zn + H2
Dd A là dd (CH3COO)2Zn
B là khí H2
b) mCH3COOH=100.18/100=18g
-->nCH3COOH=18/60=0,3
-->nZn=0,3/2=0,15 --> mZn=0,15.65=9,75g
c) nH2=0,15 --> VH2=0,15.22,4=3,6l
d) m(CH3COO)2Zn=0,3.183=54,9g
mdd=mZn + mddCH3COOH - mH2=9,75+100-0,3=109,45
-->C%=54,9/109,45.100%=50,16%
[TẶNG BẠN] TRỌN BỘ Bí kíp học tốt 08 môn
