CH3COOH --> CH3COO(-) + H(+)
Trước 0,1
Trong x --------- -----> x -------------> x
Sau 0,1 - x x x
[ CH3COO(-) ][ H(+) ]
Ka = _____________________
[ CH3COOH ]
x.x
1,8.10^(-5) = ______
0,1-x
<=> x² + 1,8.10^(-5)x - 1,8.10^(-6) = 0
<=> x = 1,3327.10^(-3)
<=> x = -1,3507.10^(-3) (loại)
=> pH = -log( 1.3327.10^(-3) ) = 2,875