điều chế metan

N

nguyenvancuong1225@gmail.com

$C_2H_2 + 2H_2O \rightarrow C_2H_2 + Ca(OH)_2 \\ \\ C_2H_2 + H_2 \xrightarrow{PbCO_3} C_2H_4 \\ \\ C_2H_4 + H_2O \rightarrow C_2H_5OH \\ \\ C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O \\ \\ CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O \\ \\ CH_3COONa + NaOH \xrightarrow{CaO} CH_4 + NaCO_3$
 
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P

phamthimai146

$C_2H_2 + 2H_2O \rightarrow C_2H_2 + Ca(OH)_2 \\ \\ C_2H_2 + H_2 \xrightarrow{PbCO_3} C_2H_4 \\ \\ C_2H_4 + H_2O \rightarrow C_2H_5OH \\ \\ C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O \\ \\ CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O \\ \\ CH_3COONa + NaOH \xrightarrow{CaO} CH_4 + NaCO_3$

Câu hỏi là dieu chế CH4 trực tiếp từ CaC2 ==> KHÔNG

Ban nguyenvancuong điều che di dường vòng
 
B

bacsipmhoang

$C_2H_2 + 2H_2O \rightarrow C_2H_2 + Ca(OH)_2 \\ \\ C_2H_2 + H_2 \xrightarrow{PbCO_3} C_2H_4 \\ \\ C_2H_4 + H_2O \rightarrow C_2H_5OH \\ \\ C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O \\ \\ CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O \\ \\ CH_3COONa + NaOH \xrightarrow{CaO} CH_4 + NaCO_3$
bạn ghi nhầm phương trình 1 rồi :)

http://*****************/present/show?entry_id=10347267
bài 1 f ý, mình nghĩ chắc sai đề
 
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