$\color{Red}{\fbox{★Hóa 9★}}\color{Magenta}{\fbox{game nối chuỗi phản ứng }}$

[hocgioi2013]

$NaOH+Al+H_2O-->NaAlO_2+H_2$
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[buivanbao123]

$NaAlO_2 + CO_2 + H_2O---> Al(OH)_3 + NaHCO_3$


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[duonghongsonmeo]

NaHCO3 + NaOH ------> Na2CO3 + H20
1111111111111111111111111111111

 

[hocgioi2013]

$Na_2CO_3+2HCl-->2NaCl+H_2O+CO_2$
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[kobato_2509]

$Na_2CO_3+2HCl-->2NaCl+H_2O+CO_2$
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$CuO +2HCl ----> CuCl_2 + H_2O$
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[buivanbao123]

$Cucl_2+AgNO_3----->AgCL+Cu(NO_3)_2$

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[kobato_2509]

$Cucl_2+AgNO_3----->AgCL+Cu(NO_3)_2$

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$Cu(NO_3)_2 + 2KOH ---> Cu(OH)_2 + 2KNO_3$
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[buivanbao123]

$kno_3+hcl---->kcl+h_2o+no_2$


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[kobato_2509]

$kno_3+hcl---->kcl+h_2o+no_2$


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Hình như không xảy ra...
Nếu xảy ra :$H_2O + BaO ----> Ba(OH)_2$

 

[phuong_july]

$kno_3+hcl---->kcl+h_2o+no_2$


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Phản ứng này không xảy ra.
Pư mới: $3FeCl_2+4HCl+KNO_3 \longrightarrow 2H_2O+KCl+NO+FeCl_3$ (đk: nhiệt độ)

 

[duonghongsonmeo]

$2FeCl3 + Fe -----> 3FeCl2$
1111111111111111111111

 

[nguyentranminhhb]

$2FeCl3 + Fe -----> 3FeCl2$

$3FeCl_2 + 4HNO_3 --> Fe(NO_3)_3 + 2FeCl_3 +NO + 2H_2O$

 

[buivanbao123]

$k_2o+h_2o----->koh$

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[flytoyourdream99]

$k_2o+h_2o----->koh$

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$KOH + FeS0_4 ----> Fe(0H)_2 + K_2S0_4$ .

 

[duonghongsonmeo]

$KOH + FeS0_4 ----> Fe(0H)_2 + K_2S0_4$ .

$ K_2SO_4 + Ba(OH)_2 -------> BaSO_4 + 2KOH $
1111111111111111111111111111111111111111

 

[flytoyourdream99]

$ k_2so_4 + ba(oh)_2 -------> baso_4 + 2koh $
1111111111111111111111111111111111111111

$koh +co_2--> k_2c0_3 + h_20$ .

 

[kobato_2509]

$koh +co_2--> k_2c0_3 + h_20$ .

$h_2o + so_3 ----->h_2so_4$
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[haycuhocmai]

$h_2o + so_3 ----->h_2so_4$
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[TEX]8H_{2}SO_{4}+2KMnO_{4}+10FeSO_{4}\rightarrow 5Fe_{2}(SO_{4})_{3}+K_{2}SO_{4}+2MnSO_{4}+H_{2}O[/TEX]
Tha hồ chọn tiếp

 

[kobato_2509]

[TEX]8H_{2}SO_{4}+2KMnO_{4}+10FeSO_{4}\rightarrow 5Fe_{2}(SO_{4})_{3}+K_{2}SO_{4}+2MnSO_{4}+H_{2}O[/TEX]
Tha hồ chọn tiếp

$Fe_2(SO_4)_3 + 6NaOH --->3Na_2SO_4 + 2Fe(OH)_3$
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[flytoyourdream99]

$Fe_2(SO_4)_3 + 6NaOH --->3Na_2SO_4 + 2Fe(OH)_3$
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$Fe(0H)_3 ---to--> Fe_20_3 + H_20$ .