$\color{Red}{\fbox{★Hóa 9★}}\color{Magenta}{\fbox{game nối chuỗi phản ứng }}$

[buivanbao123]

$Ba(OH)_2+MgCL_2---------->BaCL_2+Mg(OH)_2$

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[kobato_2509]

$Mg(OH)_2 \xrightarrow{t^o} MgO + H_2O$
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[anhto2011]

Sai, Phải là Cl2

$H_2O + BaO \rightarrow Ba(OH)_2$
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Chỉ là thiếu xót. sorry
Ba(OH)2 + P2O5 ----> Ba3(PO4)2 + H2O
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[kobato_2509]

$3H_2O + P_2O_5 \rightarrow 2H_3PO_4$
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[buivanbao123]

$H_3PO_4+BaCL_2---->HCL+Ba_3(PO_4)_2$

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[kobato_2509]

$H_3PO_4+BaCL_2---->HCL+Ba_3(PO_4)_2$

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Cái đó ko xảy ra vì axit HCl mạnh hơn axit ban đầu.
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[anhto2011]

BaCl + H2SO4 ---> Ba2SO4 + HCl
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[buivanbao123]

BaCl + H2SO4 ---> Ba2SO4 + HCl
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Ba hóa trị 2 nha bạn công thức phải là $BaSO_4$ chứ ko phải $Ba_2SO_4$

 

[anhto2011]

BaCl2 + H2SO4 ---> BaSO4 + HCl
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[buivanbao123]

$HCl+CaCO_3--------->CaCL_2+H_2O+CO_@$

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[nom1]

Ca(OH)2 + CO2 -> CaCO3 + H2O
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[kobato_2509]

$CaCO_3 \xrightarrow{t^o} CaO + CO_2$
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[nom1]

CaO + 2HCl -> CaCl2 + H2O
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[trieutml]

$ CaHC0_3 + NaN0_3----> Na_2C0_3 + CaC0_3 + HN0_3$

Na2CO3 +Ba(OH)2---->BaCO3+ 2NaOH >-
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[trieutml]

CaO + 2HCl -> CaCl2 + H2O
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CaCl2+ H2SO4----->CaSO4+2HCl >-
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[buivanbao123]

$HCL+MgO---------->MgCL_2+H_2O$

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[kobato_2509]

Chưa cân bằng nhá

$MgCl_2 \xrightarrow{t^o} Mg + Cl_2$
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[buivanbao123]

Mg+HNO_3----------->Mg(NO_3)_2+NO+H_2O$

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[anhto2011]

H_2O + BaO ----> Ba(OH)_2
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[kobato_2509]

H_2O + BaO ----> Ba(OH)_2 + H_2
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Sai
Ko có H2 đâu
$Ba(OH)_2 + H_2SO_4 \rightarrow BaSO_4 + 2H_2O$
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