$\color{Red}{\fbox{★Hóa 9★}}\color{Magenta}{\fbox{game nối chuỗi phản ứng }}$

[kobato_2509]

$ CuO + H_2 -----------t^o-----------> Cu + H_2O $

$ H_2O + BaO \rightarrow Ba(OH)_2$
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[kagaminex]

$ H_2O + BaO \rightarrow Ba(OH)_2$
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$Ba(OH)_2+H_2SO_4\rightarrow BaSO_4+2H_2O$
p/s: xl bạn mình ko thấy T.T
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[buivanbao123]

$H_2O+MgO------>Mg(OH)_2$

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[kagaminex]

$H_2O+MgO------>Mg(OH)_2$

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$Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O$
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[kobato_2509]

$Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O$
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$MgCl_2 \rightarrow Mg + Cl_2$
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[buivanbao123]

$Ag+CL---->AgCL$

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[kobato_2509]

$Ag+CL---->AgCL$

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$ AgCl \rightarrow Ag + Cl_2$
(điện phân nóng chảy)
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[kagaminex]

$ AgCl \rightarrow Ag + Cl_2$
(điện phân nóng chảy)
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$2Ag+2H_2SO_4(đ,n)\rightarrow Ag_2SO_4+SO_2+2H_2O$
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[buivanbao123]

$so_2+h_2o---------->h_2so_3$

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[kobato_2509]

$so_2+h_2o---------->h_2so_3$

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$H_2SO_3$ không tồn tại ở đk thường đâu, chỉ có trên lí thuyết thôi

 

[buivanbao123]

$so_2+h_2o---------->h_2so_3$

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[kobato_2509]

H2SO3 không tồn tại ở đk thường đâu, chỉ có trên lí thuyết thôi
Cái này hôm trước có ng thử rùi anh ạ
Anh tìm cái khác giùm e.

 

[kobato_2509]

$2Ag+2H_2SO_4(đ,n)\rightarrow Ag_2SO_4+SO_2+2H_2O$
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$2SO_2 + O_2 \rightarrow 2SO_3$

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[kagaminex]

$2SO_2 + O_2 \rightarrow 2SO_3$

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$SO_3+Na_2O\rightarrow Na_2SO_4$
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[kobato_2509]

$SO_3+Na_2O\rightarrow Na_2SO_4$
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$Na_2SO_4 + Ba(NO_3)_2 \rightarrow 2NaNO_3 + BaSO_4$
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[kagaminex]

$Na_2SO_4 + Ba(NO_3)_2 \rightarrow 2NaNO_3 + BaSO_4$
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$2NaNO_3--t^o-->2NaNO_2+O_2$
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[kobato_2509]

$2NaNO_3--t^o-->2NaNO_2+O_2$
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$Mg + O_2 \rightarrow 2MgO$
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[kagaminex]

$Mg + O_2 \rightarrow 2MgO$
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$MgO+H_2O--t^o-->Mg(OH)_2$
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[kobato_2509]

$MgO+H_2O--t^o-->Mg(OH)_2$
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$Mg(OH)_2 + H_2SO_4 \rightarrow MgSO_4 + 2H_2O$
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[kagaminex]

$Mg(OH)_2 + H_2SO_4 \rightarrow MgSO_4 + 2H_2O$
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$MgSO_4+BaCl_2\rightarrow MgCl_2+BaSO_4$
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