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cemoon


Cho tam giác ABC, chứng minh:
a) [TEX]sin2A +sin2B + sin2C \leq \sqrt{3}(cosA + cosB + cosC)[/TEX]
b)[TEX]tan^2\frac{A}{2} + tan^2\frac{B}{2} + tan^2\frac{C}{2} = \frac{4}{3}(sin^2\frac{A}{2} + sin^2\frac{B}{2} + sin^2\frac{C}{2})[/TEX]
Sử dụng BĐT Trê-Bư-Sép
a) [TEX]sin2A +sin2B + sin2C \leq \sqrt{3}(cosA + cosB + cosC)[/TEX]
b)[TEX]tan^2\frac{A}{2} + tan^2\frac{B}{2} + tan^2\frac{C}{2} = \frac{4}{3}(sin^2\frac{A}{2} + sin^2\frac{B}{2} + sin^2\frac{C}{2})[/TEX]
Sử dụng BĐT Trê-Bư-Sép
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