[tex]\frac{x + 16}{\sqrt{x} + 3}[/tex]
= [tex]\frac{x - 9 + 25}{\sqrt{x} + 3}[/tex]
= [tex]\sqrt{x} - 3 + \frac{25}{\sqrt{x} + 3}[/tex]
= [tex]\sqrt{x} + 3 + \frac{25}{\sqrt{x} + 3} - 6[/tex]
= [tex]\geq 2\sqrt{(\sqrt{x} + 3).\frac{25}{\sqrt{x} + 3}} - 6[/tex]
= 2.5 - 6 = 4
Dấu "=" xảy ra<=> x = 4
Vậy Min P = 4 <=> x = 4