BT về HNO3

L

l94

nMg=0,04
[tex] Mg-->Mg^{+2}+2e[/tex]
ne=0,08
[tex]N^{+5}+xe-->N^{5-x}[/tex]
[tex]n_{N^{5-x}}=0,08=\frac{0,08}{x}[/tex] x=1, sinh ra NO2
 
T

thent

Ta có : nMg = 0.04 mol
nX =0.08 mol
sử dụng ĐLBTe
Mg \RightarrowMg+2 +2e
0.04 0.08

N+5 +5x-2y \Rightarrow N2Y/X
0.08 0.08
0.08*(5X-2Y) =0.08
\Rightarrow5x-2y=1

\Rightarrowx=1; y=2:\Rightarrowno2
 
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