bai hoa can cac ban giup do

M

mua_sao_bang_98

ptpu: $ 2H_2 + O_2 -^{t^0}-> 2H_{2}O$

$CO_2 không phản ứng với O_2 $

$n_{O_2}= \frac{81,6}{22,4}=\frac{51}{14}$

\Rightarrow $ n_{H_2}=2.\frac{51}{14}=\frac{51}{7}$

\Rightarrow$ m_{H_2}=\frac{51}{7}.2=14,57 gam$

\Rightarrow$ m CO_2 = 68-14,57=43,42 gam$
:)
 
M

mua_sao_bang_98

ptpu: $ 2H_2 + O_2 -^{t^0}-> 2H_{2}O$

$CO_2 không phản ứng với O_2 $

$n_{O_2}= \frac{81,6}{22,4}=\frac{51}{14}$

$ n_{H_2}=2.\frac{51}{14}=\frac{51}{7}$

$ m_{H_2}=\frac{51}{7}.2=14,57 gam$

$ m CO_2 = 68-14,57=43,42 gam$
:)
 
C

conan_trinhtham

loi giai

có PTPU : [TEX]2H_2+O_2------>2H_2O[/TEX]
có [TEX]n_O_2[/TEX]=[TEX]\frac{81.6}{22.4}[/TEX]=[TEX]\frac{51}{14}[/TEX]
\Rightarrow[TEX]n_H_2[/TEX]=[TEX]\frac{51}{14}[/TEX]. 2 = [TEX]\frac{51}{7}[/TEX]
\Rightarrow[TEX]m_H_2[/TEX]=2.[TEX]\frac{51}{7}[/TEX]=14.57g
\Rightarrow[TEX]m_CO_2[/TEX]= 68-14.57=53.43g(*)(*)(*)(*)(*)(*)
 
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