Cau1)
goi CTTQ cua este la RCOOR' co ptpu sau
RCOOR' + H2O ->R'OH + RCOOH
0,15...................................0,15
RCOOH + KOH -> RCOOK + H2O
0,15...........0,2.......0,15
=>khoi luong ran sau pu gom: 0,05 mol KOH va 0,15mol RCOOK (vi ancol bay hoi khi co can dd)
=>khoi luong ran...