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hoàng nhầm mà hoàng sửa lại rồi đó

a)$ \frac{15(x^3y^5-20x^4y^4-5x^5y^5)}{(-5x^3y^2)}\\=\frac{15(x^3y^4)(y-20x-5xy)}{(-5x^3y^2)}\\=-3y^2(y-20x-5xy)\\=-3y^3+60xy^2+15xy^3$ c) $\frac{(x^3-8)}{(x^2+2x+4)}\\=\frac{(x-2)(x^2+2x+4)}{x^2+2x+4}\\=x-2$

a)Bạn viết đề lại nha b)$\frac{5a^2x^4-3a^2x^2}{a^2x^2}=42\\\Leftrightarrow \frac{(a^2x^2)(5x^2-3)}{a^2x^2}=42\\\Leftrightarrow 5x^2-3=42\\\Leftrightarrow x^2=\frac{42+3}{5}\\\Leftrightarrow x^2=9$ Giải tiếp ra x= cộng trừ 3 Vậy....

I have several good friends but I suppose that my best friend is Hanh. We have been friends with each other since we were very young because of she used to live next door to me. We have always been in the same class at school, although she has always been much more cleverer than me. I don't mind...

Mình làm tiếp nhé 3.It is the first time she has been to the ballet. 4.This is the first time she has drunk Coca cola. 5.It is the first time I've read this book. 6.It is the first time I've met such an intelligent student. 7.This is the first time I've seen snow. 8.My grandfather has never...

Giả sử $ x + y + z = \frac{1}{x}+\frac{1}{y}+\frac{1}{z}=0$ $\\\Rightarrow x+y+z=0(1)$ Và $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=0(2)$ Từ 2 suy ra: $\frac{yz+xz+xy}{xyz}=0\\\Rightarrow xy+xz+yz=0$ Từ 1 suy ra: $ (x+y+z)^2=0\\\Leftrightarrow x^2+y^2+z^2+2xy+2yz+2xz=0\\\Leftrightarrow...

Chị Giang

1. While Bob (sleep) was sleeping, the phone (ring) was ringing. 2. I'd rather you (go) went to bed now. 3. The woman (sit) sat in front of me was wearing a big hat so I couldn't see anything. 4. Radium (discover) was discovered by Marie and Pierre Curie in 1898. 5. I ( not understand) didn't...

$101^2-99^2+1\\=(101-99)(101+99)+1\\=2.200+1\\=400+1\\=401$

$M=x^{15}- 8x^{14}+8x^{13}- 8x^{12}+...- 8x^{2}+8x-5\\=x^{15}-(x+1)x^{14}+(x+1)x^{13}-(x+1)x^{12}+...-(x+1)x^{2}+(x+1)x-5\\=x^{15}-x^{15}-x^{14}+x^{14}+x^{13}-x^{13}-x^{12}+...-x^{3}-x^2+x^2+x-5\\=x+5\\=7-5=2$

1/Mạng internet có phải là mạng Wan không? Vì sao?

a) $(x-3)^2 + (x-11)^2\\=x^2-6x+9+x^2-22x+121\\=2x^2-28x+130\\=2(x^2-14x+65)\\=2(x^2-2.x.7+49+16)\\=2[(x-7)^2+16]\\=2(x-7)^2+32\geq 32$ Vậy....

theo mình, khi nghị luận cả bài thơ không cần trích hết thơ ra, mình sẽ dẫn nhập thơ khi phân tích ở phần thân bài.

vì x=9 nên 10=x+1 rồi thế vào

$P=x^{10}-10x^9+10x^8-10x^7+....-10x+10 \\=x^{10}-(x+1)x^9+(x+1)x^8-(x+1)x^7+...-(x+1)x+10\\=x^{10}-x^{10}-x^9+x^9+x^8-x^8-x^7+...-x^2-x+10\\=-x+10\\=10-x\\=10-9\\=1$

Gọi 4 góc trong tứ giác lần lượt là : a,b,c,d (360>a,b,c,d>0) Áp dụng tính chất dãy tỉ số bằng nhau, ta có: $\frac{a}{1}=\frac{b}{2}=\frac{c}{3}=\frac{d}{4}=\frac{a+b+c+d}{1+2+3+4}=\frac{360}{10}=36\\\Rightarrow a=36\\b=36.2=72\\c=36.3=108\\d=36.4=144$ Vậy: ............