BaO + 2H2O -----> Ba(OH)2 + H2
n BaO= 0.15 mol
=> n Ba(OH)2 = 0.15 mol
Th1 Ba(OH)2 dư
Ba(OH)2 + CO2 -----> BaCo3 + H2O
n BaCO3 = 197/19.7=0.1 mol
=> nCO2 = 0.1 mol => V Co2 = 2.24 l
Th2 Ba(OH)2 hết
Ba(OH)2 + CO2 -----> BaCo3 + H2O
0.15______0.15______0.15_______
BaCO3 + H2O + CO2 ----->...