2Na +2H2O--->2NaOH + H2(1)
2C2H5OH +2Na----->2C2H5ONa +H2(2)
VC2H5OH=96.10/100=9,6ml
----->VH2O=10 - 9,6=0,4ml
-->mH2O=0,4g-->nH2O=0,02mol
mC2H5OH=9,6.0,8=7,68g--->nC2H5OH=0,17mol
--->nH2(1)=0,1mol
nH2(2)=0,085mol
--------->VH2=22,4(0,17+0,085)=2,128l
V hỗn hợp rượu=10+10,6=20,6ml
--->độ...