Kết quả tìm kiếm

giúp em vớiạ, emđang cần gấạ

d. \dfrac{x^2 - 2x + 3}{x - 2} > 0 f. \dfrac{x^2 + 3x - 5}{x^2 + 4} \ge 1 Giúp em với em đang cần ạ

chị ơi, giải luôn câu b cho em với ạ, em cảm ơn

Giúp em với ạ, em cảm ơn a, 3-x/x+2>0 b, x-5/x-7bé hơn hoặc = 1

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