nhận xét: [tex]1-\frac{1}{n^2}=\frac{n^2-1}{n^2}=\frac{(n-1).(n+1)}{n^2}[/tex]
áp dụng: [tex]N=\frac{2.4}{3^2}.\frac{3.5}{4^2}.\frac{4.6}{5^2}.....\frac{11.13}{12^2}\\\\ =(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}....\frac{11}{12}).(\frac{4}{3}.\frac{5}{4}.\frac{6}{5}.....\frac{13}{12})\\\\ =\frac{1}{6}.\frac{13}{3}=\frac{13}{18}[/tex]