C
chirikurin


Cau 4: phan bt co huong dan. Em co the lam theo cach nay khong?
[tex]\frac{V S.MBC}{V SABC} = \frac{SM}{SA}. \frac{SB}{SB}.\frac{SC}{SC}= \frac{1}{2} [/tex]khong? Co phai k dc su dung ti le nhu the nay k thay?
[tex]\frac{V S.MBC}{V SABC} = \frac{SM}{SA}. \frac{SB}{SB}.\frac{SC}{SC}= \frac{1}{2} [/tex]khong? Co phai k dc su dung ti le nhu the nay k thay?
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