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M

my_nguyen070

hoa 8

$n_{H_2SO_4}$ =0,05 MOL
PU: $MO+H_2SO_4----> MSO_4+H_2O$.
0,05 mol 0,05 mol 0,05 mol
MMO=4:0,05=80 g
mM=M+16=80 => M=64(Cu)
mCuSO4=0,05.160=8g

Chú ý Latex.
 
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