phần c;d gợi ý còn tự làm nhé!
c.[tex]\frac{3x+7}{x-1}=\frac{3x-3+10}{x-1}=\frac{3(x-1)+10}{x-1}=3+\frac{10}{x-1}...................[/tex]
d.[tex]\frac{4x-1}{3-x}=\frac{1-4x}{-(3-x)}=\frac{12-4x-11}{-(3-x)}=\frac{4(3-x)-11}{-(3-x)}=\frac{11-4(3-x)}{3-x}=\frac{11}{3-x}-1[/tex]