[toán] lượngHelp me !!!

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huutrang93

Cm phương trình lượng giác :
[TEX]cos^6x - sin^6x = (15/16)cos2x + (1/16)cos6x[/TEX]

[TEX]cos^6x - sin^6x=(cos^2x-sin^2x)(cos^4x+sin^4x+sin^2x.cos^2x)[/TEX]
[TEX]=cos2x[(cos^2x+sin^2x)-sin^2x.cos^2x]=cos2x(1-sin^2x.cos^2x)=\frac{cos2x}{4}(4-sin^22x[/TEX]
[TEX]=\frac{cos2x}{4}(cos^22x+3)=\frac{4cos^32x+12cos2x}{16}=\frac{15cos2x+4cos^32x-3cos2x}{16}[/TEX]
[TEX]=\frac{15cos2x+cos6x}{16}[/TEX]
 
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