[TEX]\sqrt{3}.sin^2x -sinx.cosx = 0 \\ sin x ( \sqrt{3}sin x - cosx) = 0 \\ sin x = 0 \Rightarrow x = k.\pi \\ \sqrt{3}sin x - cosx = 0 \Rightarrow \sqrt{3}sin x = cosx \Rightarrow \sqrt{3}tan x = 1 \Rightarrow tan x = \frac{\sqrt{3}}{3} \Rightarrow x= \frac{\pi}{6} + k.\pi[/TEX]