Toán khó

T

toiyeu9a3

Bài 1:
$2^k.C_n^k = (1 + 1)^k. C_n^k = \sum\limits_{k =0}^{n}C_n^k.C_n^k = \sum\limits_{m =0}^kC_n^mC_{n - m}^{k -m}$
 
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