Nguyentrang1111139.
[imath]\cos{\alpha}=\dfrac{|\overrightarrow{BD}.\overrightarrow{CK}|}{BD.CK}=\dfrac{|-2\overrightarrow{BC}^2|}{4BD.CK}=\dfrac{BC^2}{2BD.CK}[/imath]
mà [imath]2BD.CK \leq BD^2+CK^2=\dfrac{5}{4}BC^2[/imath]
nên [imath]\cos{\alpha} \geq \dfrac{4}{5}[/imath]