Nguyentrang11111
38. [imath]S=\sqrt{p(p-a)(p-b)(p-c)} \leq \dfrac{(a+b+c)^2}{12\sqrt3}[/imath] (1)
Áp dụng định lý cosin
[imath] tử=\dfrac{a^2+b^2+c^2}{2}\geq \dfrac{(a+b+c)^2}{6}[/imath] (2)
Từ (1) và (2) suy ra [imath]Q \leq 2\sqrt3[/imath]
Nguyentrang1111139.
[imath]\cos{\alpha}=\dfrac{|\overrightarrow{BD}.\overrightarrow{CK}|}{BD.CK}=\dfrac{|-2\overrightarrow{BC}^2|}{4BD.CK}=\dfrac{BC^2}{2BD.CK}[/imath]
mà [imath]2BD.CK \leq BD^2+CK^2=\dfrac{5}{4}BC^2[/imath]
nên [imath]\cos{\alpha} \geq \dfrac{4}{5}[/imath]