[tex]x-(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{2019.2020})=(\frac{4}{3}-0,5):\frac{13}{4}=\frac{5}{6}:\frac{13}{4}=\frac{10}{39}[/tex]
Lại có:[tex]\frac{1}{2}+\frac{1}{6}+...+\frac{1}{2019.2020}=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2019.2020}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2019}-\frac{1}{2020}=1-\frac{1}{2020}=\frac{2019}{2020}[/tex]
[tex]\Rightarrow x=\frac{2019}{2020}+\frac{10}{39}[/tex]