[Toán 8_Đại số] Giải phương trình

N

nhuquynhdat

2) $\dfrac{2-x}{2011}-1=\dfrac{1-x}{2012}-\dfrac{x}{2013}$

\Rightarrow $1+\dfrac{2-x}{2011}-2=\dfrac{1-x}{2012}+1+1-\dfrac{x}{2013}-2$

\Rightarrow $\dfrac{2013-x}{2011}-2=\dfrac{2013-x}{2012}-\dfrac{2013-x}{2013}-2$

\Rightarrow $\dfrac{2013-x}{2011}-\dfrac{2013-x}{2012}-\dfrac{2013-x}{2013}=0$

\Rightarrow $(2013-x)(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013})=0$

\Rightarrow $(2013-x)=0$ \Rightarrow $x=2013$
 
N

nhuquynhdat

1)$\dfrac{x+9}{57}+ \dfrac{x+7}{59}+\dfrac{x+5}{61}+\dfrac{x+3}

{63}+\dfrac{x+1}{65}=1$

\Rightarrow $\dfrac{x+9}{57}+1+ \dfrac{x+7}{59}+1+\dfrac{x+5}{61}+1+\dfrac{x+3}

{63}+1+\dfrac{x+1}{65}+1=1+5$

\Rightarrow $\dfrac{x+66}{57}+ \dfrac{x+66}{59}+\dfrac{x+66}{61}+\dfrac{x+66}

{63}+\dfrac{x+66}{65}=6$

\Rightarrow $(x+66)(\dfrac{1}{57}+ \dfrac{1}{59}+\dfrac{1}{61}+\dfrac{1}

{63}+\dfrac{1}{65})=6$

\Rightarrow $x+66=6$ \Rightarrow $x=-60$
 
Last edited by a moderator:
Top Bottom